pu_inst_anim
Author: pg
Date: 13 March 2013

Eq. (8.3) - 2ème t.

{Im}

$\underline{Z}$

Puissance instantanée : p(t)

p_{totale}  =  terme actif  +  terme réactif

{Re)

U I cosφ

EPFL-LAI - P. Germano & A. Boegli - 2013, Rév. 2022

Eq. (8.3) - 1er t.

Eq. (8.1)

Eq. 8.1  $p(t) = U I \cos\varphi + UI \cos(2 \omega t + \alpha + \beta)$

Eq. 8.3  $p(t) = UI\cos\varphi [1 + \cos(2 \omega t + 2 \alpha)] + U I \sin \varphi \sin(2 \omega t + 2 \alpha)$

Eq1

Eq3

H_t = 5 (slider from 0 to 8, step 0.5)
U = 2
I = 1 (slider from -5 to 5, step 1)
α_1 = 0 (slider from -6.28 to 6.28, step 0.314)
ω = 1
φ = 0.75 (slider from -1.575 to 1.575, step 0.025)
p_r(x) = (((U * I) * sin(φ)) * sin(((2 * ω) * x) + (2 * α_1)))
A = (9, 6)
B = (9, 5)
C = (9, 7)
c = CircleArc(A, B, C)
D = (10.6, 6)
E = (9, 4.6)
F = (9, 7.6)
e_{Im} = Vector(E, F)
G = (9, 6)
Z: (9 + cos(φ), 6 + sin(φ))
e_Z = Vector(G, Z)
J: (4.25, H_t)
H: (3.1, H_t)
a = Segment(H, J)
K: (4.8, H_t)
L: (6.2, H_t)
b = Segment(K, L)
M: (1.9, H_t)
N: (2.65, H_t)
d = Segment(M, N)
e_{Re} = Vector(A - (0.2, 0), D)
p_{moy}(x) = ((U * I) * cos(φ))
p_a(x) = (((U * I) * cos(φ)) * (1 + cos(((2 * ω) * x) + (2 * α_1))))
p(x) = (((U * I) * cos(φ)) * (1 + cos(((2 * ω) * x) + (2 * α_1)))) + (((U * I) * sin(φ)) * sin(((2 * ω) * x) + (2 * α_1)))
O: (0.5, -3.75)
P: (12.5, -3.75)
Q_1: (14, -2)
R_1: (12, -2)
u = Vector(Q_1, R_1)
Q_3: (14, -3)
R_3: (12, -3)
v = Vector(Q_3, R_3)
bool_1 = true
bool_3 = false
actif_1: (2.7, -3.4)
actif_2: (6.9, -3.4)
actif = Segment(actif_1, actif_2)
réactif_1: (7.4, -3.4)
réactif_2: (10.8, -3.4)
réactif = Segment(réactif_1, réactif_2)